Bitwise XOR the right operand with the left operand and assign the result to the left operand.

This is functionally equivalent to the expression:

anOperand1 = anOperand1 ^ anOperand2;

Performs a bit-by-bit XOR of the 32-bit value derived from both operands.

Where a corresponding bit is different in both operands, a 1 bit will be inserted into the result. If the corresponding bit is identical in both operands, regardless of whether they both have a 1 bit or a zero bit, a zero will be inserted at that bit position in the result.

Although this is classified as an assignment operator it is really a compound of an assignment and a bitwise operator.

The associativity is right to left.

Refer to the Operator Precedence topic for details of execution order.

The new value of anOperand1 is returned as a result of the expression.

This is the truth table for two Boolean primitive values being operated on with the XOR operator.

The bitwise operator performs this operation on each corresponding bit pair in the two operands.

Warnings:

• The operand to the left of the operator must be an LValue. That is, it should be able to take an assignment and store the value.

Cross-references:

ECMA 262 edition 2 - section - 11.13

ECMA 262 edition 3 - section - 11.13